利用switch語句解決問題：定期存款利息計算器

利?switch語句解決問題：定期存款利息計算器

1#include

2int main ( )

3{

4 int type;

5 double money, period, rate, interest;

6 printf("歡迎使?利息計算器！n");

7 printf("請輸?存款?額：");

8 scanf("%lf", &money);

9 printf("======存款期限======n");

10 printf("1. 3個? n");

11 printf("2. 6個?n");

12 printf("3. ?年 n");

13 printf("4. ?年n");

14 printf("5. 三年n");

15 printf("6. 五年n");

16 printf("請輸?存款期限的代號：");

17 scanf("%d", &type);

18 if (type>=1 && type <=6)

19 {

20 switch(type) //在if中嵌?了switch分情況處理

21 {

22 case 1:

23 period = 0.25;

24 rate = 0.031;

25 break;

26 case 2:

27 period = 0.5;

28 rate = 0.033;

29 break;

30 case 3:

31 period = 1;

32 rate = 0.035;

33 break;

34 case 4:

35 period = 2;

36 rate = 0.044;

37 break;

38 case 5:

39 period = 3;

40 rate = 0.05;

41 break;

42 case 6:

43 period = 5;

44 rate = 0.055;

45 break;

46 }

47 interest = money * period * rate;

48 printf("到期利息為：%.2lf 元，本息合計共 %.2lf 元。n", interest, interest + money);

49 }

50 else

51 printf("選擇存款類型錯誤！n");

52 printf("感謝您的使?，歡迎下次光臨！n");

53 return 0;

54}